Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 8 - Complex Numbers, Polar Equations, and Parametric Equations - Section 8.5 Polar Equations and Graphs - 8.5 Exercises - Page 395: 63

Answer

$x = \frac{y^2}{4}-1$ We can see the graph below:

Work Step by Step

$r = \frac{2}{1-cos~\theta}$ $r-r~cos~\theta = 2$ $\sqrt{x^2+y^2}-x = 2$ $\sqrt{x^2+y^2} = x+2$ $x^2+y^2 = x^2+4x+4$ $y^2 = 4x+4$ $x = \frac{y^2}{4}-1$ We can see the graph below:
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.