Answer
$x=±2i\sqrt 3$
Work Step by Step
$x^{2}+12=0$
$x^{2}=-12$
$x=±\sqrt -12$
$x=±(\sqrt 4\times\sqrt 3\times\sqrt -1)$
$x=±2i\sqrt 3$
We know that $\sqrt 4=2$, because $2^{2}=4$.
We know that $\sqrt -1=i$, because $-1^{2}=i$.
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