Answer
$x=±4i$
Work Step by Step
$x^{2}=-16$
$x=±\sqrt -16$
$x=±(\sqrt 16\times\sqrt -1)$
$x=±4i$
We know that $\sqrt 16=4$, because $4^{2}=16$.
We know that $\sqrt -1=i$, because $-1^{2}=i$.
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