Answer
$0$
Work Step by Step
RECALL:
Since $\cos{x}$ and $\cos^{-1}{x}$ are inverse functions of each other, then, for all valid values of $x$,
$\cos^{-1}{(\cos(x))}=x$
Thus,
$\cos^{-1}{(\cos{(0)})}=0$
Trigonometry (11th Edition) Clone
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
978-0-13-421743-7
ISBN 13:
978-0-13421-743-7
Chapter 6 - Review Exercises - Page 291: 28
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