Answer
Since $sin(A+B)$ is positive and $cos(A+B)$ is negative, the quadrant of $A+B$ must be quadrant II.
Work Step by Step
$sin(A+B) = \frac{33}{65}$
$cos(A+B) = -\frac{56}{65}$
Since $sin(A+B)$ is positive and $cos(A+B)$ is negative, the quadrant of $A+B$ must be quadrant II.
