Answer
$sec^2~B = \frac{1}{cos^2~B} = \frac{1}{1-sin^2~B}$
Work Step by Step
We can verify the identity:
$sec^2~B = \frac{1}{cos^2~B} = \frac{1}{1-sin^2~B}$
Trigonometry (11th Edition) Clone
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
978-0-13-421743-7
ISBN 13:
978-0-13421-743-7
Chapter 5 - Test - Page 250: 10
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