Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 4 - Quiz (Sections 4.1-4.2) - Page 164: 8

Answer

$y=2 \sin x$

Work Step by Step

Upon inspection, we find that the graph shows a sin function with an amplitude of 2 and a period of $2\pi$. In the equation $y=a \sin bx$, $a$ is the amplitude. Since the amplitude is 2, $a$ is equal to 2. To find the value of $b$, we use the formula: Step 1: Period$=\frac{2\pi}{b}$ Step 2: $2\pi=\frac{2\pi}{b}$ Step 3: $b=\frac{2\pi}{2\pi}$ Step 4: $b=1$ Substituting the values of $a$ and $b$ in the equation $y=a \sin bx$, we find that the equation of the graph is $y=2 \sin x$.
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