Answer
$y = 2+sin~(2x-\pi)$
We can see the graph below.
The period is $\pi$
The amplitude is $1$
Work Step by Step
$y = 2+sin~(2x-\pi)$
When $x = 0$, then $y = 2+sin~(-\pi) = 2$
When $x = \frac{\pi}{4}$, then $y = 2+sin~(-\frac{\pi}{2}) = 1$
When $x = \frac{\pi}{2}$, then $y = 2+sin~(0)= 2$
When $x = \frac{3\pi}{4}$, then $y = 2+sin~(\frac{\pi}{2}) = 3$
When $x = \pi$, then $y = 2+sin~(\pi) = 2$
We can see the graph below.
The period is $\pi$
The amplitude is $1$
