Chapter 2 - Acute Angles and Right Triangles - Section 2.5 Further Applications of Right Triangles - 2.5 Exercises - Page 88: 32

$x = 146.5$ meters

1. $\tan \theta_1 = \frac{68.7}{x_2}$ $x_2 = \frac{68.7}{\tan 16^{\circ} 50'}\approx 242.242695$ 2. $\tan \theta_2 = \frac{68.7}{x_1}$ $x_1 = \frac{68.7}{\tan 36^{\circ} 40'}\approx 95.723635$ 3. $x= x_2 - x_1$ $x \approx 146.5$ meters