Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 2 - Acute Angles and Right Triangles - Section 2.2 Trigonometric Functions of Non-Acute Angles - 2.2 Exercises - Page 63: 71

Answer

225$^{\circ}$ 315$^{\circ}$

Work Step by Step

1) Since cscθ is negative, θ must lie in quadrants III or IV. Since the absolute value of cscθ is $\sqrt 2$, the reference angle, θ must be 45°. 2) The quadrant III angle θ equals 180$^{\circ}$ +45$^{\circ}$ =225$^{\circ}$ and the quadrant IV angle θ equals 360$^{\circ}$ - 45$^{\circ}$ = 315$^{\circ}$.
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