Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 2 - Acute Angles and Right Triangles - Section 2.2 Trigonometric Functions of Non-Acute Angles - 2.2 Exercises - Page 63: 68

Answer

300$^{\circ}$ 240$^{\circ}$

Work Step by Step

1) $\sin$$\theta$ = -$\frac{\sqrt 3}{2}$ 2) Since $\sin$$\theta$ is negative, $\theta$ lies in either 3rd or 4th quadrant. 3)The reference angle is 60 $^{\circ}$ since absolute value of the sin $\theta$ is 60$^{\circ}$ 4)The angle in quadrant 3 is 180$^{\circ}$ + 60$^{\circ}$ =240$^{\circ}$ 5)The angle in quadrant 4 is 360$^{\circ}$ - 60$^{\circ}$ =300$^{\circ}$
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