Answer
$\tan$ 41$^{\circ}$ $\lt$ $\cot $41$^{\circ}$ is true.
Work Step by Step
$\tan$ 41 < $\cot$ 41
We must first get the inequality in terms of $\tan$
$\cot$ $A$ = $\tan$ (90$^{\circ}$ - $A$)
Therefore:
$\cot$ 41 = $\tan$(90$^{\circ}$ - 41$^{\circ}$)
$\cot$ 28 = $\tan$ 49$^{\circ}$
The inequality could be rewritten: $\tan$ 41 < $\cot$ 49
From 0$^{\circ}$ to 90$^{\circ}$, as the angle increases, the $tangent$ of the angle increases.
Therefore: $\tan$ 41$^{\circ}$ $\lt$ $\tan$ 49$^{\circ}$ is true.
Therefore: $\tan$ 41$^{\circ}$ $\lt$ $\cot $41$^{\circ}$ is true.
