Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 2 - Acute Angles and Right Triangles - Section 2.1 Trigonometric Functions of Acute Angles - 2.1 Exercises - Page 54: 21

Answer

$\cos$ 30$^{\circ}$ = $\sin$ 60$^{\circ}$

Work Step by Step

$\cos$ $A$ = $\sin$ (90$^{\circ}$ - $A$) Therefore: $\cos$ 90$^{\circ}$ = $\cos$ (90$^{\circ}$ - 30$^{\circ}$) = $\sin$ 60$^{\circ}$ Therefore: $\cos$ 30$^{\circ}$ = $\sin$ 60$^{\circ}$
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