Answer
{$\pm4$}
Work Step by Step
According to the square root property,
if $x^{2}=16$
then $x=\sqrt (16)=4$ or $x=-\sqrt (16)=-4$
Therefore, the solution set is{$-4,+4$} or {$\pm4$}
Trigonometry (11th Edition) Clone
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
978-0-13-421743-7
ISBN 13:
978-0-13421-743-7
Appendix A - Equations and Inequalities - Page 420: 43
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
