Answer
P(A) = P(A head appears on the coin)
= P{(1,H),(3,H),(5,H)}
= 3 x 1/12
= 1/4 = 0.25
P(B) = P(he die is tossed only one time)
= P{(1,H),(1,T),(3,H),(3,T),(5,H),(5,T)}
= 6 x 1/12
= 1/2 = 0.5
Work Step by Step
As given in answer