Answer
There is sufficient evidence to support that the mean weight of newborn Chinese babies is less than 3369.
Work Step by Step
$H_{0}:\mu=3369$. $H_{a}:\mu < 3369.$ Hence the value of the test statistic: $\frac{\overline{x}-\mu}{s/\sqrt n}=\frac{3171-3369}{428/\sqrt{1862}}=-19.962.$ The P-value is the corresponding probability in the table, hence P is less than 0.005. If the P-value is less than $\alpha$, which is the significance level, then this means the rejection of the null hypothesis. Hence:P is less than $\alpha=0.01$, because it is less than 0.005, hence we reject the null hypothesis. Hence we can say that there is sufficient evidence to support that the mean weight of newborn Chinese babies is less than 3369.
