Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 8 - Polar Coordinates; Vectors - Section 8.4 Vectors - 8.4 Assess Your Understanding - Page 627: 74

Answer

$F=94 i+34.2 j $

Work Step by Step

We know that the magnitude of horizontal component of force is given by: $F=||v||cos\alpha$ where $||v||$ is the magnitude of the force and $\alpha$ is the direction angle. Similarly, the magnitude of vertical component of force is given by: $F=||v||sin\alpha$ Thus, we have: $F_i=||v|| \cos\alpha=(100) \cos 20^\circ=94$, and $F_j=||v|| \sin \alpha=100 \sin 20^\circ=34.2$ Therefore, the components of the force vector are: $F=94 i+34.2 j $
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.