Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 8 - Polar Coordinates; Vectors - Section 8.4 Vectors - 8.4 Assess Your Understanding - Page 627: 48

Answer

$-j$

Work Step by Step

Let us consider two vectors $v=pi+qj$ and $w=xi+yj$; then we have the unit vector $u$ in the same direction as $v$ given by: $u=\dfrac{v}{||v||}$ and the magnitude of any vector (let us say $v$) can be determined using the formula $||v||=\sqrt{p^2+q^2} $ We have: $||v||=\sqrt {0^2+(-3)^2}=3$ Therefore, $u=\dfrac{v}{||v||}=\dfrac{ -3j}{3}=-j$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.