Answer
$2y\sqrt[3] {3x^2y^2}$
Work Step by Step
Based on the given conditions, we have:
$\sqrt[3] {24x^2y^5}=\sqrt[3] {3\cdot 2^3x^2y^2y^3}=2y\sqrt[3] {3x^2y^2}$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 8 - Polar Coordinates; Vectors - Section 8.3 The Complex Plane; De Moivre's Theorem - 8.3 Assess Your Understanding - Page 616: 72
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