Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 8 - Polar Coordinates; Vectors - Section 8.3 The Complex Plane; De Moivre's Theorem - 8.3 Assess Your Understanding - Page 616: 71

Answer

$240^{\circ}=\dfrac{4 \pi}{3}$

Work Step by Step

Using $\pi=180^{\circ}$, we have $240^{\circ}=180^{\circ}+60^{\circ}$ $=\pi+\dfrac{\pi}{3}$ $=\dfrac{3 \pi+\pi}{3}$ $=\dfrac{4 \pi}{3}$
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