Answer
$\frac{\sqrt 3}{2},-\frac{1}{2}$
Work Step by Step
Based on the given conditions, we have:
$sin120^\circ=sin(180^\circ-60^\circ)=sin60^\circ=\frac{\sqrt 3}{2}$, $cos240^\circ=cos(180^\circ+60^\circ)=-cos60^\circ=-\frac{1}{2}$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 8 - Polar Coordinates; Vectors - Section 8.3 The Complex Plane; De Moivre's Theorem - 8.3 Assess Your Understanding - Page 614: 4
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