Answer
See graph, $\sqrt 2(cos135^\circ+i\ sin135^\circ)$
Work Step by Step
1. See graph for $z=-1+i$ 2. $z=-1+i=\sqrt
2(-\frac{\sqrt 2}{2}+i\frac{\sqrt 2}{2})=\sqrt 2(cos135^\circ+i\ sin135^\circ)$
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