Answer
$x^2+(y-1)^2=1$
a circle with center $(0,1)$, radius $r=1$.
See graph.
Work Step by Step
1. Use the formula $r^2=x^2+y^2, r\ sin\theta=y$, we have $r=2sin\theta\rightarrow r^2=2r\ sin\theta \rightarrow x^2+y^2=2y \rightarrow x^2+(y-1)^2=1$
2. We can identify the above equation as a circle with center $(0,1)$, radius $r=1$.
3. See graph.
