Answer
$(x-1)^2+y^2=1$
a circle with center $(1,0)$, radius $r=1$.
See graph.
Work Step by Step
1. Use the formula $r^2=x^2+y^2, r\ cos\theta=x$, we have $r=2cos\theta\rightarrow r^2=2r\ cos\theta \rightarrow x^2+y^2=2x \rightarrow (x-1)^2+y^2=1$
2. We can identify the above equation as a circle with center $(1,0)$, radius $r=1$.
3. See graph.
