Answer
$(5,0.93)$, $(-5,4.07)$
Work Step by Step
1. Given $(3,4)$ (in quadrant I) in rectangular coordinates, we have $r=\sqrt {9+16}=5$ and $\theta=tan^{-1}\frac{4}{3}\approx0.93$, thus we have $(5,0.93)$ in polar coordinates for $r\gt0$.
2. For $r\lt0$, we can choose $(-5,\pi+0.93)$ or $(-5,4.07)$ for the same point.
