Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 8 - Polar Coordinates; Vectors - Chapter Review - Review Exercises - Page 654: 1

Answer

See graph, $(\frac{3\sqrt 3}{2},\frac{3}{2})$

Work Step by Step

1. See graph for $(3,\frac{\pi}{6})$ in polar coordinates. 2. We can find $x=3cos(\frac{\pi}{6})=\frac{3\sqrt 3}{2}$ and $y=3sin(\frac{\pi}{6})=\frac{3}{2}$ which gives $(\frac{3\sqrt 3}{2},\frac{3}{2})$ in rectangular coordinates.
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