Answer
amplitude$=2$, period$= \pi$, phase shift$=\frac{\pi}{2}$.
See graph.
Work Step by Step
1. Given $y=2sin(2x-\pi)$, we can determine the amplitude$=2$, period$=\frac{2\pi}{2}=\pi$, and phase shift$=\frac{\pi}{2}$.
2. See graph.
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