Answer
$ \frac{9\pm\sqrt {17}}{4}$
Work Step by Step
$2x^2-9x+8=0$,
$x=\frac{9\pm\sqrt {9^2-4(2)(8)}}{2(2)}\\
=\frac{9\pm\sqrt {17}}{4}$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 6 - Analytic Trigonometry - Section 6.3 Trigonometric Equations - 6.3 Assess Your Understanding - Page 491: 122
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