Answer
(a) $ -4$.
(b) $ -12$.
Work Step by Step
Given $f(\theta)=sec\theta$ (an even function) with $f(a)=-4$, we have:
(a) $f(-a)=f(a)=-4$.
(b) $f(a)+f(a+2\pi)+f(a+4\pi)=sec(a)+sec(a+2\pi)+sec(a+4\pi)=3sec(a)=-12$.
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 5 - Trigonometric Functions - Section 5.3 Properties of the Trigonometric Functions - 5.3 Assess Your Understanding - Page 419: 117
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