Answer
$(-\infty,-1]\cup[1,\infty)$.
Work Step by Step
The range of $f(\theta)=sec\theta=\frac{1}{cos\theta}$ is $(-\infty,-1]\cup[1,\infty)$.
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 5 - Trigonometric Functions - Section 5.3 Properties of the Trigonometric Functions - 5.3 Assess Your Understanding - Page 419: 105
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