Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 4 - Exponential and Logarithmic Functions - Section 4.4 Logarithmic Functions - 4.4 Assess Your Understanding - Page 324: 138

Answer

$12$

Work Step by Step

The average rate of change from $x=a$ to $x=b$ is given by the formula: $$\dfrac{f(b)-f(a)}{b-a}$$ The average rate of change of $f(x)=9^x$ from $a=\frac{1}{2}=0.5$ to $b=1$ is: \begin{align*}&=\dfrac{f(1)-f\left(\frac{1}{2}\right)}{1-\frac{1}{2}}\\ \\&=\dfrac{9^{1}-9^{\frac{1}{2}}}{1 / 2}\\ \\&=\dfrac{9-\sqrt{9}}{\frac{1}{2}}\\ \\&=\dfrac{9-3}{\frac{1}{2}}\\ \\&=\dfrac{6}{\frac{1}{2}}\\ \\&=6 \cdot \frac{2}{1}\\ \\&=12 \end{align*}
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