Answer
Zeros $ \pm\frac{1}{2}, \pm3$.
x-intercepts $\pm\frac{1}{2}, \pm3$.
Work Step by Step
1. Zeros $4x^4-37x^2+9=0 \Longrightarrow (4x^2-1)(x^2-9)=0 \Longrightarrow x^2=\frac{1}{4}, 9 \Longrightarrow x=\pm\frac{1}{2}, \pm3$.
2. The x-intercepts are $x=\pm\frac{1}{2}, \pm3$.
