Chapter 4 - Exponential and Logarithmic Functions - Section 4.3 Exponential Functions - 4.3 Assess Your Understanding - Page 307: 96

(a) $240$, $(-5,240)$. (b) $-3$, $(-3,24)$. (c) $-1$.

(a) Given $F(x)=(\frac{1}{3})^x-3$, we have $F(-5)=(\frac{1}{3})^{-5}-3=240$ which gives point $(-5,240)$. (b) $24=F(x)=(\frac{1}{3})^x-3$, thus $x=-3$ which gives point $(-3,24)$ on the graph. (c) $F(x)=(\frac{1}{3})^x-3=0$, we have $x=-1$.