Answer
See graph.
domain $(-\infty,\infty)$, range $(0,\infty)$, H.A. $y=0$.
Work Step by Step
Step 1. To obtain the graph of $f(x)=e^{x+2}$ from $y=e^x$, shift the curve 2 units to the left. See graph.
Step 2. We can determine the domain $(-\infty,\infty)$, range $(0,\infty)$, horizontal asymptote H.A. $y=0$.