Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 4 - Exponential and Logarithmic Functions - Section 4.3 Exponential Functions - 4.3 Assess Your Understanding - Page 306: 27

Answer

Exponential function and $H (x)=4^x$.

Work Step by Step

We can see that the ratio of consecutive vales is fixed or constant. That is, $\dfrac{1}{1/4}=\dfrac{4}{1}=\dfrac{16}{4}=\dfrac{4}{1}$ Thus, the function is an exponential function with a common ratio of $4$. The difference of consecutive vales is not fixed or constant. That is, $4-1=3 \ne 16-4=12$ Thus, the function is not a linear function. So, we conclude that the function with common ratio $4$ and $H(0)=1$ has the model: $H (x)=Ca^x=1(4)^x=4^x$.
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