Answer
domain $\{x|x\ne-\frac{3}{2},2 \}$.
H.A. $y=3$, V.A. $x=-\frac{3}{2}$.
Work Step by Step
Step 1. $R(x)=\frac{6x^2-11x-2}{2x^2-x-6}=\frac{(6x+1)(x-2)}{(2x+3)(x-2)}=\frac{6x+1}{2x+3}, x\ne2$, thus we have the domain $\{x|x\ne-\frac{3}{2},2 \}$.
Step 2. We can identify the horizontal asymptote H.A. $y=3$, vertical asymptote V.A. $x=-\frac{3}{2}$, oblique asymptote O.A. $none$.