Chapter 3 - Polynomial and Rational Functions - Section 3.3 Complex Zeros; Fundamental Theorem of Algebra - 3.3 Assess Your Understanding - Page 231: 27

$3+2i,-2,5$.

Step 1. As $x=3-2i$ is a zero, we have $x=3+2i$ also a zero and $(x-3-2i)(x-3+2i)=(x-3)^2+4=x^2-6x+13$ is a factor of the function. Step 2. Use synthetic division (two steps) or long division (as shown in the figure) to get the quotient. Step 3. Find other zeros $x^2-3x-10=0 \Longrightarrow (x-5)(x+2)=0 \Longrightarrow x=-2,5$.