Answer
$f(x)=x^3-3x^2-4x+12$
Work Step by Step
Let us consider that $a$ is a zero of the function with multiplicity $b$. Then this factor of the function can be expressed as: $(x-a)^b$.
We are given that the degree is $3$, and the zeros are $-2$, $2$ and $3$.
Therefore, we can write the equation of the function as:
$f(x)=a(x+2)(x-2)(x-3)\\=a(x^3-3x^2-4x+12)$
When $a=1$, the function can be written as:
$f(x)=x^3-3x^2-4x+12$
