Answer
two distinct real solutions.
Work Step by Step
Given $2x^2+3x-4=0$, we have $a=2,b=3,c=-4$ and $b^2-4ac=3^2-4(2)(-4)=41\gt0$, thus the equation has two distinct real solutions.
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 2 - Linear and Quadratic Functions - Section 2.7 Complex Zeros of a Quadratic Function* - 2.7 Assess Your Understanding - Page 178: 27
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