Answer
$-2\pm2i$
See graph.
Work Step by Step
Step 1. $x^2+4x+8=0 \longrightarrow x^2=\frac{-4\pm\sqrt {16-4(8)}}{2}=-2\pm2i$
Step 2. See graph.
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 2 - Linear and Quadratic Functions - Section 2.7 Complex Zeros of a Quadratic Function* - 2.7 Assess Your Understanding - Page 178: 14
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