Answer
$f(x)=\dfrac{x-3}{\ln x}$ is continuous for all real numbers except for $1$.
Work Step by Step
Given: $f(x)=\dfrac{x-3}{\ln x}$
We can see that the $x$ in the denominator cannot be zero and $x \ne 1$ because $\ln 1=0$.
The fraction function is continuous everywhere, except for where it is undefined. So, $f(x)=\dfrac{x-3}{\ln x}$ is continuous for all real numbers except for $1$.
