Answer
$-119$
Work Step by Step
The determinant for a 3 by 3 matrix can be computed as: $Determinant (D)= \begin{vmatrix} A & B & C \\
a & b & c \\
g &h & i \\ \end{vmatrix}=A(ei-fh)-B(di-fg)+C(dh-eg)$
Therefore, $D=3 [(4) (1) -(-3)(0)]+9(1)(1)-(8)(0)]+4[(1)(-3)-(8)(4)]\\=(3)(4) +(9)(1)+(4)(-35) \\=12+9-140 \\=-119$