Answer
$-26$
Work Step by Step
The determinant for a 3 by 3 matrix can be computed as: $Determinant (D)= \begin{vmatrix} A & B & C \\
a & b & c \\
g &h & i \\ \end{vmatrix}=A(ei-fh)-B(di-fg)+C(dh-eg)$
Therefore, $D=4 [(-1) (4) -(0)(-3)]+1[(6)(4)-(1)(0)]+(2)[(6)(-3)-(1)(-1)]\\=(4)(-4) +1(24)+(2)(-17) \\=-16+24-34 \\=-26$