Answer
(a) $d(x) =\sqrt {x^2-x+1}$
(b) See graph.
(c) $x=0.5$
Work Step by Step
(a) $d(x)=\sqrt {(x-1)^2+(y-0)^2}=\sqrt {x^2-2x+1+(\sqrt x)^2}=\sqrt {x^2-x+1}$
(b) See graph.
(c) Minimum of $d(x)$ at $x=0.5$
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