Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 1 - Functions and Their Graphs - Section 1.6 Mathematical Models: Building Functions - 1.6 Assess Your Understanding - Page 103: 1

Answer

(a) $d(x)= \sqrt {x^4-15x^2+64}$ (b) $d(0)= 8$ (c) $d(1)= \sqrt {50}\approx7.07$ (d) See graph. (e) $x=\pm2.74$

Work Step by Step

(a) $d(x)=\sqrt {x^2+y^2}=\sqrt {x^2+(x^2-8)^2}=\sqrt {x^4-15x^2+64}$ (b) $d(0)=\sqrt {0^4-15(0)^2+64}=8$ (c) $d(1)=\sqrt {1^4-15(1)^2+64}=\sqrt {50}\approx7.07$ (d) See graph. (e) Minima of $d(x)$ at $x=\pm2.74$
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