Answer
See graph and explanations.
Work Step by Step
1. Given $y=3-4sin(\frac{5}{2}x+\pi)=-4sin[\frac{5}{2}(x+\frac{2\pi}{5})]+3$, we have amplitude $4$, period $p=\frac{2\pi}{5/2}=\frac{4\pi}{5}$.
2. Graph $y=sin(x)$ (blue), shift $\frac{2\pi}{5}$ to the left, shrink horizontally by a factor of $\frac{5}{2}$, then stretch vertically by a factor of 4, reflect around the x-axis, then shift up 3 units to get $y=3-4sin(\frac{5}{2}x+\pi)$ (red).
