Answer
See graph and explanations.
Work Step by Step
1. Given $y=2-sec[\pi(x-3)]=2-\frac{1}{cos[\pi(x-3)]}$, we have period $p=\frac{2\pi}{\pi}=2$.
2. Graph $y=-cos[\pi(x-3)]$ (blue), use reciprocal property to get $y=-sec[\pi(x-3)]$, then shift 2 units up to get $y=2-sec[\pi(x-3)]$ (red).
