Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 6 - The Circular Functions and Their Graphs - Quiz - Page 616: 8

Answer

$\frac{2\pi}{3}$

Work Step by Step

If $s\in[\frac{\pi}{2},\pi]$, it is in quadrant II, with $sin(s)=\frac{\sqrt 3}{2}$, we have $s=\frac{2\pi}{3}$
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