Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 6 - The Circular Functions and Their Graphs - Quiz - Page 616: 5

Answer

$\frac{\sqrt 2}{2}$

Work Step by Step

Since $\frac{7\pi}{4}$ is in quadrant IV with a reference angle $\theta=2\pi-\frac{7\pi}{4}=\frac{\pi}{4}$, we have $cos(\frac{7\pi}{4})=cos(\frac{\pi}{4})=\frac{\sqrt 2}{2}$
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