Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 6 - The Circular Functions and Their Graphs - Chapter 6 Test Prep - Review Exercises - Page 644: 15

Answer

$$ - {110^ \circ }$$

Work Step by Step

$$\eqalign{ & - \frac{{11\pi }}{{18}} \cr & {\text{Multiply by }}\frac{{{{180}^ \circ }}}{\pi }. \cr & - \frac{{11\pi }}{{18}}{\text{radians}} = - \frac{{11\pi }}{{18}}\left( {\frac{{{{180}^ \circ }}}{\pi }} \right) \cr & {\text{Simplify}} \cr & - \frac{{11\pi }}{{18}}{\text{radians}} = - \frac{{{{1980}^ \circ }}}{{18}} \cr & - \frac{{11\pi }}{{18}}{\text{radians}} = - {110^ \circ } \cr} $$
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